AP Inter 2nd Year Maths 2A Answer Key 2026 (Unofficial) – Check Section-Wise Solutions

Students can now review the section-wise solutions and exam analysis to compare their responses and estimate their expected marks in the Intermediate Public Examination.

The Board of Intermediate Education Andhra Pradesh (BIEAP) conducted the Maths 2A exam from 9:00 AM to 12:00 PM across various exam centres in the state.

The question paper carried 75 marks for theory, while 25 marks were allotted for internal/practical assessment, making the total 100 marks.

With the exam completed, students are now checking the AP Inter Maths 2A Answer Key 2026 to verify their answers, understand the difficulty level of the paper, and estimate their performance before the official results are declared.

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AP Inter 2nd Year Maths 2A Unofficial Answer Key 2026

AP Inter 2nd Year Maths 2A Answer Key 2026 – Section A Solutions

Below are the answers for Section A (Very Short Answer Questions) from the AP Inter 2nd Year Mathematics Paper IIA exam conducted on 4 March 2026.

Question 1: Find the square root of 3 + 4i.

• Answer: ±(2 + i)

Question 2: Find Arg(z₁) + Arg(z₂) if Arg(z₁̅) = π/5 and Arg(z₂) = π/3.

• Answer: 2π / 15

• Explanation: Since Arg(z₁) = −Arg(z₁̅) = −π/5.

Question 3: Find the value of xyz where x, y, z = cis A, cis B, cis C and A + B + C = π.

• Answer: −1

• Explanation: Using cis(A + B + C) = cis(π) = cos π + i sin π.

Question 4: Form the quadratic equation whose roots are 7 ± √25.

• Answer: x² − 14x + 29 = 0

Question 5: Find the transformed equation with negative roots of x⁴ + 5x³ + 11x + 3 = 0.

• Answer: x⁴ − 5x³ − 11x + 3 = 0

• Explanation: Replace x with −x in the given equation.

Question 6: Find the number of derangements of 4 letters in 4 envelopes.

• Answer: 9

• Explanation: Using the formula D_n = n! [1 − 1/1! + 1/2! − 1/3! + 1/4!].

Question 7: Find 13C_n if nC₅ = nC₆.

• Answer: 78

• Explanation: Since nC₅ = nC₆, n = 5 + 6 = 11. Therefore 13C₁₁ = 78.

Question 8: Find the number of terms in (2x + 3y + z)⁷.

• Answer: 36

• Explanation: Using the formula (n + r − 1)! / [(r − 1)! n!] where n = 7 and r = 3.

Question 9: Find the variance of 6, 7, 10, 12, 13, 4, 8, 12.

• Answer: 9.25

• Explanation: Mean x̄ = 9 and variance σ² = (1/n) Σ(x_i − x̄)².

Question 10: Find P(X = 5) if P(X = 1) = P(X = 2) for a Poisson variable.

• Answer: (15/32)e⁻² ≈ 0.2873

• Explanation: The mean λ = 2.

Section B Solutions

Question 11: Identify the type of quadrilateral formed by the points A(2,1), B(4,3), C(2,5), and D(0,3).

Solution:

Given points:

• A(2, 1), B(4, 3), C(2, 5), D(0, 3)

Length of sides:

• AB = √[(4−2)² + (3−1)²] = √(4 + 4) = √8

• BC = √[(2−4)² + (5−3)²] = √(4 + 4) = √8

• CD = √[(0−2)² + (3−5)²] = √(4 + 4) = √8

• DA = √[(2−0)² + (1−3)²] = √(4 + 4) = √8

All four sides are equal.

Length of diagonals:

• AC = √[(2−2)² + (5−1)²] = √16 = 4

• BD = √[(4−0)² + (3−3)²] = √16 = 4

Since all sides are equal and diagonals are equal, the quadrilateral is a Square.

Question 12: Find the range of the function \( y = \frac{x}{x^2 - 5x + 9} \).

Solution:

Let

• y = x / (x² − 5x + 9)

Multiplying both sides:

• y(x² − 5x + 9) = x

• yx² − 5yx + 9y − x = 0

• yx² − (5y + 1)x + 9y = 0

This is a quadratic equation in x.

For real values of x, discriminant D ≥ 0.

• D = (5y + 1)² − 4(y)(9y)

• D = 25y² + 10y + 1 − 36y²

• D = −11y² + 10y + 1 ≥ 0

Solving the inequality:

Range of y = [-1/11 , 1]

Question 13: Find the rank of the word REMAST when arranged in dictionary order.

Solution:

Word: REMAST

• Letters: A, E, M, R, S, T

Total letters = 6

Count the number of words that appear before REMAST.

• Words starting with A: 5! = 120

• Words starting with E: 5! = 120

• Words starting with M: 5! = 120

Total so far = 360

Next, consider words starting with R.

• Second letter smaller than E → A

• RA _ _ _ → 4! = 24

• Next, consider words starting with RE.

• Third letter smaller than M → A

• REA _ _ → 3! = 6

• Finally, the word REMAST itself.

Total Rank = 120 + 120 + 120 + 24 + 6 + 1

Final Rank = 391

AP Inter 2nd Year Maths 2A Question Paper Pattern 2026

The Mathematics Paper IIA followed the standard Intermediate exam pattern with three sections.

Section A

• Very short answer questions

• Objective or short-type

• Lower mark weightage

Section B

• Short answer questions

• Requires working steps

• Medium difficulty

Section C

• Long answer or problem-solving questions

• Higher mark weightage

• Requires detailed mathematical solutions

AP Inter 2nd Year Maths 2A Important Topics

Based on recent exam trends and syllabus weightage, the following topics had significant importance:

• Binomial Theorem

• Probability

• Random Variables and Probability Distributions

• Complex Numbers

• De Moivre’s Theorem

• Theory of Equations

• Permutations and Combinations

• Vectors and related concepts

How to Calculate Marks Using the Unofficial Answer Key

After checking the unofficial answer key, students can estimate their expected score by comparing their responses with the correct answers.

First, mark all the questions you answered correctly in each section of the paper. Then multiply the number of correct answers by the marks allotted for each question in that section.

Next, add the marks from Section A, Section B, and Section C to get your approximate score out of 75 marks (theory).

This method provides a rough idea of your performance, although the final marks may vary slightly during the official evaluation by BIEAP.

Disclaimer:

The answers and solutions provided above are based on available question papers and expert analysis. They are intended only for reference to help students estimate their performance. The final marks will be determined by the official evaluation conducted by the Board of Intermediate Education, Andhra Pradesh (BIEAP).